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JSP请求到Controller，Contr6oller可以请求到Service里处理，照源照或者自己处理，拍s拍webview浏览器源码构造WebService客户端实例，照源照然后调用Webservice。拍s拍php会员空间源码
Webservice里获得数据库连接，照源照魔域 外挂 源码打开并查询数据库信息，拍s拍就是照源照你的那张“cim_subscrb_”表，然后返回。拍s拍
然后再返回给JSP显示出来。照源照
拍s拍求jsp登录源码 急急急急急急急急急急急
拍s拍登陆页面 index.jsp源码：
拍s拍<%@ page language="java" import="java.util.*" pageEncoding="utf-8"%>
拍s拍<%
拍s拍String path = request.getContextPath();
拍s拍String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
拍s拍%>
拍s拍<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4. Transitional//EN">
拍s拍<html>
拍s拍<head>
拍s拍<base href="<%=basePath%>">
拍s拍<title>login</title>
拍s拍<meta .jci.upload.servlet;
拍s拍import java.io.File;
拍s拍import java.io.FileOutputStream;
拍s拍import java.io.IOException;
拍s拍import java.io.InputStream;
拍s拍import java.io.OutputStream;
拍s拍import java.util.List;
拍s拍import javax.servlet.ServletException;
拍s拍import javax.servlet..jci.upload.servlet.UploadServlet</servlet-class>
拍s拍</servlet>
拍s拍<servlet-mapping>
拍s拍<servlet-name>UploadServlet</servlet-name>
拍s拍<url-pattern>/UploadServlet</url-pattern>
拍s拍</servlet-mapping>
拍s拍<welcome-file-list>
拍s拍<welcome-file>index.jsp</welcome-file>
拍s拍</welcome-file-list>
拍s拍</web-app>
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