1.这个飞狐的飞狐副图飞狐拦截码java源码副如何修改才能用来作为通达信的副呢?
这个飞狐的副如何修改才能用来作为通达信的副呢?
rsv:=(c-llv(l,7))/(hhv(h,7)-llv(l,7))*;
rsv1:=(c-llv(l,))/(hhv(h,)-llv(l,))*;
流金:sma(rsv1,5,1),colorfff;
岁月:sma(流金,,1),colorcc;
drawband(流金,rgb(,0,0),岁月,rgb(0,,0));
var2q:=ma(c,)-ma(c,)/3;
神奇线:=ma((c-var2q)/var2q,1);
xa:=ema(神奇线,)*0.7;
xb:=ema(神奇线,3);
底部区域:if(llv(xb-xa,)>0,0,-),Linethick2,colorff;
diff:=(ema(c,)-ema(c,))*;
dea:=ema(diff,);
macd:=2*(diff-dea);
stickline(diff<=0 and dea<=diff and ref(diff,1)<ref(dea,1),3,,3,0),Linethick2,colorffff;
if(diff<=0 and dea<=diff and ref(diff,1)<ref(dea,1),,0),colorff;
var1:=(c-ref(c,1))/ref(c,1)*;
var2:=(indexc-ref(indexc,1))/ref(indexc,1)*;
var3:=ema(sum(var1,),3);
var4:=ema(sum(var2,),3);
var5:=(var3-var4);
drawicon(var5<- and filter(var5>ref(var5,2),7),0,1);
drawicon(var5> and filter(var5<ref(var5,2),7),,2);
a1:=ma(c,);
zx:=ref(a1,/2+1);
b1:=cross(c,zx);
s1:=cross(zx,c);
drawicon(cross(c,zx),-3,);
drawicon(c>zx and ref(c,1)>ref(zx,1),-3,);
drawicon(c<zx and ref(c,1)>ref(zx,1),-3,);
lgl:=c-ref(ma(c,),);
wr1:=if(ema(c,5)/ema(ema(c,9),)<=0. and c/ref(c,1)>0. and c/ref(c,1)<1. and v/capital*<5,,0);
wr2:=-(*(hhv(h,)-c)/(hhv(h,)-llv(l,)))+*lgl;
wr3:=-(*(hhv(h,)-c)/(hhv(h,)-llv(l,)))+;
bias1:=-(*(hhv(h,)-c)/(hhv(h,)-llv(l,)))+*lgl;
bias2:=((c-ma(c,))/ma(c,)*+)*5;
bias3:=((c-ma(c,))/ma(c,)*+)*5;
sx:=((c-ma(c,))/ma(c,)*+)*5;
s:=(wr2+wr3+bias1+bias2+bias3+sx)/6*lgl;
ccc:=abs(bias2-sx);
zjz:=(s+ccc)/2;
lxl:=(-1)*(ema(*(1-winner(c)),1)-)+;
jbj:=lxl+zjz;
ma3:=if(wr1>0 and jbj<0,,0)*lgl;
c0:=if(zjz<0 and c=llv(c,5) and c/ref(c,1)>0. and c/ref(c,1)<1. and v/capital*<5,-,0);
bot:=if(jbj<0 and c0=-,,0)*lgl;
cxc:=ref(c,2)*0.;
vmc:=ref(c,)*0.;
v:=min(cxc,vmc);
v:=*v/capital*lgl;
半年线:=(c-v)/c<3/ and sum(v,5)/5<1.8;
预测:=半年线>0 and (c0<0 or wr1>0);
if(ma3>0 and bot>0 and sum(v/capital*,5)/5<1 or 半年线>0 and ref(c,1)/ref(c,2)>0. or
(ma3>0 and bot>0 and sum(v/capital*,5)/5<1 or 半年线>0) and (c0<0 or wr1>0) and 预测<,,0),Linethick2,colorffff;
a:=ema(winner(c),);
b:=ema(winner(c),);
var:=ma(v,5)>ma(v,);
追涨:if(a<0. and abs(a-b)<0. and cross(a,b) and var,,0),Linethick2,colorffcc;
if(a>0.9 and c<ma(c,5),,),Linethick2,colorred;
sma(var,3,1),colorfff0;
股神:3*sma((c-llv(l,))/(hhv(h,)-llv(l,))*,5,1)-2*sma(sma((c-llv(l,))/(hhv(h,)-llv(l,))*,5,1),3,1),colorff;
短线进出:if(股神<=,-,0);
if(cross(股神,)AND 岁月<,,0),Linethick2;